\(\int \frac {x \cos (a+b x)}{\sin ^{\frac {9}{2}}(a+b x)} \, dx\) [351]

Optimal result

Integrand size = 18, antiderivative size = 88 \[ \int \frac {x \cos (a+b x)}{\sin ^{\frac {9}{2}}(a+b x)} \, dx=-\frac {12 E\left (\left .\frac {1}{2} \left (a-\frac {\pi }{2}+b x\right )\right |2\right )}{35 b^2}-\frac {2 x}{7 b \sin ^{\frac {7}{2}}(a+b x)}-\frac {4 \cos (a+b x)}{35 b^2 \sin ^{\frac {5}{2}}(a+b x)}-\frac {12 \cos (a+b x)}{35 b^2 \sqrt {\sin (a+b x)}} \]

[Out]

12/35*(sin(1/2*a+1/4*Pi+1/2*b*x)^2)^(1/2)/sin(1/2*a+1/4*Pi+1/2*b*x)*EllipticE(cos(1/2*a+1/4*Pi+1/2*b*x),2^(1/2
))/b^2-2/7*x/b/sin(b*x+a)^(7/2)-4/35*cos(b*x+a)/b^2/sin(b*x+a)^(5/2)-12/35*cos(b*x+a)/b^2/sin(b*x+a)^(1/2)

Rubi [A] (verified)

Time = 0.06 (sec) , antiderivative size = 88, normalized size of antiderivative = 1.00, number of steps used = 4, number of rules used = 3, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.167, Rules used = {3524, 2716, 2719} \[ \int \frac {x \cos (a+b x)}{\sin ^{\frac {9}{2}}(a+b x)} \, dx=-\frac {12 E\left (\left .\frac {1}{2} \left (a+b x-\frac {\pi }{2}\right )\right |2\right )}{35 b^2}-\frac {4 \cos (a+b x)}{35 b^2 \sin ^{\frac {5}{2}}(a+b x)}-\frac {12 \cos (a+b x)}{35 b^2 \sqrt {\sin (a+b x)}}-\frac {2 x}{7 b \sin ^{\frac {7}{2}}(a+b x)} \]

[In]

Int[(x*Cos[a + b*x])/Sin[a + b*x]^(9/2),x]

[Out]

(-12*EllipticE[(a - Pi/2 + b*x)/2, 2])/(35*b^2) - (2*x)/(7*b*Sin[a + b*x]^(7/2)) - (4*Cos[a + b*x])/(35*b^2*Si
n[a + b*x]^(5/2)) - (12*Cos[a + b*x])/(35*b^2*Sqrt[Sin[a + b*x]])

Rule 2716

Int[((b_.)*sin[(c_.) + (d_.)*(x_)])^(n_), x_Symbol] :> Simp[Cos[c + d*x]*((b*Sin[c + d*x])^(n + 1)/(b*d*(n + 1
))), x] + Dist[(n + 2)/(b^2*(n + 1)), Int[(b*Sin[c + d*x])^(n + 2), x], x] /; FreeQ[{b, c, d}, x] && LtQ[n, -1
] && IntegerQ[2*n]

Rule 2719

Int[Sqrt[sin[(c_.) + (d_.)*(x_)]], x_Symbol] :> Simp[(2/d)*EllipticE[(1/2)*(c - Pi/2 + d*x), 2], x] /; FreeQ[{
c, d}, x]

Rule 3524

Int[Cos[(a_.) + (b_.)*(x_)^(n_.)]*(x_)^(m_.)*Sin[(a_.) + (b_.)*(x_)^(n_.)]^(p_.), x_Symbol] :> Simp[x^(m - n +
1)*(Sin[a + b*x^n]^(p + 1)/(b*n*(p + 1))), x] - Dist[(m - n + 1)/(b*n*(p + 1)), Int[x^(m - n)*Sin[a + b*x^n]^
(p + 1), x], x] /; FreeQ[{a, b, p}, x] && LtQ[0, n, m + 1] && NeQ[p, -1]

Rubi steps \begin{align*} \text {integral}& = -\frac {2 x}{7 b \sin ^{\frac {7}{2}}(a+b x)}+\frac {2 \int \frac {1}{\sin ^{\frac {7}{2}}(a+b x)} \, dx}{7 b} \\ & = -\frac {2 x}{7 b \sin ^{\frac {7}{2}}(a+b x)}-\frac {4 \cos (a+b x)}{35 b^2 \sin ^{\frac {5}{2}}(a+b x)}+\frac {6 \int \frac {1}{\sin ^{\frac {3}{2}}(a+b x)} \, dx}{35 b} \\ & = -\frac {2 x}{7 b \sin ^{\frac {7}{2}}(a+b x)}-\frac {4 \cos (a+b x)}{35 b^2 \sin ^{\frac {5}{2}}(a+b x)}-\frac {12 \cos (a+b x)}{35 b^2 \sqrt {\sin (a+b x)}}-\frac {6 \int \sqrt {\sin (a+b x)} \, dx}{35 b} \\ & = -\frac {12 E\left (\left .\frac {1}{2} \left (a-\frac {\pi }{2}+b x\right )\right |2\right )}{35 b^2}-\frac {2 x}{7 b \sin ^{\frac {7}{2}}(a+b x)}-\frac {4 \cos (a+b x)}{35 b^2 \sin ^{\frac {5}{2}}(a+b x)}-\frac {12 \cos (a+b x)}{35 b^2 \sqrt {\sin (a+b x)}} \\ \end{align*}

Mathematica [A] (verified)

Time = 0.34 (sec) , antiderivative size = 73, normalized size of antiderivative = 0.83 \[ \int \frac {x \cos (a+b x)}{\sin ^{\frac {9}{2}}(a+b x)} \, dx=-\frac {2 \left (5 b x+6 \cos (a+b x) \sin ^3(a+b x)-6 E\left (\left .\frac {1}{4} (-2 a+\pi -2 b x)\right |2\right ) \sin ^{\frac {7}{2}}(a+b x)+\sin (2 (a+b x))\right )}{35 b^2 \sin ^{\frac {7}{2}}(a+b x)} \]

[In]

Integrate[(x*Cos[a + b*x])/Sin[a + b*x]^(9/2),x]

[Out]

(-2*(5*b*x + 6*Cos[a + b*x]*Sin[a + b*x]^3 - 6*EllipticE[(-2*a + Pi - 2*b*x)/4, 2]*Sin[a + b*x]^(7/2) + Sin[2*
(a + b*x)]))/(35*b^2*Sin[a + b*x]^(7/2))

Maple [F]

\[\int \frac {x \cos \left (x b +a \right )}{\sin \left (x b +a \right )^{\frac {9}{2}}}d x\]

[In]

int(x*cos(b*x+a)/sin(b*x+a)^(9/2),x)

[Out]

int(x*cos(b*x+a)/sin(b*x+a)^(9/2),x)

Fricas [F(-2)]

Exception generated. \[ \int \frac {x \cos (a+b x)}{\sin ^{\frac {9}{2}}(a+b x)} \, dx=\text {Exception raised: TypeError} \]

[In]

integrate(x*cos(b*x+a)/sin(b*x+a)^(9/2),x, algorithm="fricas")

[Out]

Exception raised: TypeError >>  Error detected within library code:   integrate: implementation incomplete (co
nstant residues)

Sympy [F(-1)]

Timed out. \[ \int \frac {x \cos (a+b x)}{\sin ^{\frac {9}{2}}(a+b x)} \, dx=\text {Timed out} \]

[In]

integrate(x*cos(b*x+a)/sin(b*x+a)**(9/2),x)

[Out]

Timed out

Maxima [F]

\[ \int \frac {x \cos (a+b x)}{\sin ^{\frac {9}{2}}(a+b x)} \, dx=\int { \frac {x \cos \left (b x + a\right )}{\sin \left (b x + a\right )^{\frac {9}{2}}} \,d x } \]

[In]

integrate(x*cos(b*x+a)/sin(b*x+a)^(9/2),x, algorithm="maxima")

[Out]

integrate(x*cos(b*x + a)/sin(b*x + a)^(9/2), x)

Giac [F]

\[ \int \frac {x \cos (a+b x)}{\sin ^{\frac {9}{2}}(a+b x)} \, dx=\int { \frac {x \cos \left (b x + a\right )}{\sin \left (b x + a\right )^{\frac {9}{2}}} \,d x } \]

[In]

integrate(x*cos(b*x+a)/sin(b*x+a)^(9/2),x, algorithm="giac")

[Out]

integrate(x*cos(b*x + a)/sin(b*x + a)^(9/2), x)

Mupad [F(-1)]

Timed out. \[ \int \frac {x \cos (a+b x)}{\sin ^{\frac {9}{2}}(a+b x)} \, dx=\int \frac {x\,\cos \left (a+b\,x\right )}{{\sin \left (a+b\,x\right )}^{9/2}} \,d x \]

[In]

int((x*cos(a + b*x))/sin(a + b*x)^(9/2),x)

[Out]

int((x*cos(a + b*x))/sin(a + b*x)^(9/2), x)